sin^2x+3cosxsinx+1=0

sin²x+3cosxsinx+1=02sin²x+3cosxsinx+cos²x=0  /cos²x≠02tg²x+3tgx+1=0tgx=a2a²+3a+1=0D=9-8=1a1=(-3-1)/4=-1⇒tgx=-1⇒x=-π/4+πna2=(-3+1)/4=-1/2⇒tgx=-1/2⇒x=-arctg0,5+πn