Решите неравенство:
0.01-х^2>0

1)0.01х²>10.01х²-1>0y=0.01х²-10.01х²-1=00.01х²=1x²=100x=+-10x ∈ [-10;10]2)0.01х²>1y=0.01х²-10.01х²-1=00.01х²=1x²=100x=+-10x∈ (-∞;-10) U (10;+∞)3) 1\2x²>121\2x²-12>0y=1\2x²-121\2x²-12=01\2x²=12x²=24x=+-√24