решите задание по теме степенная функция (3) срочно!11!

а) = (a^(7/6)) ^(-6/7) = a^(7/6  * - 6/7) = a^(-1) = 1/ a.б) = b^(5/6) * b^(7/12) = b^(5/6  + 7/12) = b^(10/12 + 7/12)= b^(17/12).3. y = y '(x0)*(x - x0) + y(x0);x0 = - 1; y = 4/3 * x^(3/4) - x^(-3) ;y(1) = 4/3 * 1 - 1 = 14/3 - 1 = 1/3;y '(x) = 4/3  * 3/4 * x^(-1/4) + 3x^(-4)= x^(-1/4) + 3* x^(-4);y '(1) = 1^(-3/4) + 3*1^(-4) = 1 + 3 = 4.y = 4(x- 1) + 1/3 = 4x - 4 + 1/3 = 4x - 11/3