Прошу вас.. помогите.. 
5cosx+2sinx = 3

5cos²(x/2)-5sin²(x/2)+4sin(x/2)cos(x/2)-3sin²(x/2)-3cos²(x/2)=08sin²(x/2)-4sin(x/2)cos(x/2)-2cos²(x/2)=0  /cos²(x/2)≠08tg²(x/2)-4tg(x/2)-2=0tg(x/2)=a4a²-2a-1=0D=4+16=20a1=(2-2√5)/2=1-√5⇒tg(x/2)=1-√5⇒x/2=arctg(1-√5)+πn⇒x=2arctg(1-√5)+2πna2=(2+2√5)/2=1+√5⇒tg(x/2)=1+√5⇒x/2=arctg(1+√5)+πn⇒2arctg(1+√5)+2πn