Решить Уравнение: 3x³-4x²-5x+2=0

3x^3 - 4x^2 - 5x + 2 = 0;(3x^3 - 4x^2 - 4x) - (x-2) = 0;x(3x^2 - 4x - 4) - (x-2) = 0;3x^2 - 4x - 4 = 0; D = 16 + 48 = 64;x1 = 2; x2 = - 4/3;3x^2 - 4x - 4 = 3(x-2) (x + 4/3) = (x-2)(3x+4);x(3x^2 - 4x - 4) - (x-2) =0;x(x-2)(3x+4) - (x-2) = 0;(x-2)(x(3x+4) - 1) = 0;(x-2)(3x^2 + 4x - 1) = 0;x - 2=0; x= 2;4x^2 + 4x - 1= 0;D = 16 + 16 = 32=(4sgrt2)^2;x = ( -1+sgrt2)/2; x2 = (-1- sgrt2) /2.