Решите систему уравнений
3х - ху = 10
у + ху = 6

3x - xy = 10y + xy = 6x(3-y) = 10y+xy = 6x = 10/(3-y)y + 10y/(3-y) = 6y(3-y) + 10y = 6(3-y)3y - y2 + 10y = 18 - 6yy2 - 6y - 13y + 18 = 0y2 - 19y + 18 = 0y1 = 18y2 = 1x1:18 + 18x = 63 + 3x = 1x = -2 / 3x2:1 + x = 6x = 5