Решите неравенства:
А) log1/2(2x+1)>-2
Б)(1/4)^х'2-6<(1/2)^10х

А) log1/2(2x+1)>-2(1/2)^ (-2) = 2x + 12x = 3x = 3/2x = 1,5Б)   (1/4)^х'2-6<(1/2)^10х(1)2)^(2x^2 - 12) < (1/2)^(10x)Так как   o< 1/2  < 1, то2x^2 - 12 > 10x2x^2 - 10x - 12 > 0x^2 - 5x - 6 > 0x1 = - 1x2 = 6x∈( -≈; -1)  (6; +≈)