7cos2x+3sin²2x=3 помогите

7cos2x + 3sin^2(2x) = 37cos2x + 3sin^2(2x) - 3 = 07 cos(2x) - 3cos^(2x) = 0cos(2x) * (3cos(2x-7)) = 01)  cos2x = 02x = π/2 + πn, n∈Zx= π/4 + (πn)/2, n∈Z2)  3cos(2x) 7cos(2x) = 7/32x = c0s^(-1)(7/3) + πk, k∈Zx2 = 1/2cos^(-1) (7/3)  + πk, k∈Z2x = 2πm - cos^(-1)(7/3) + πm, m∈Zx3 = πm - (1/2)*cos^(-1)(7/3), m∈Z