Решить уравнение [tex] \sqrt[4]{16 ^{x+1} } +188=8*2^{x} -0.5^{3-x} [/tex]

(16^(x+1)^1/4  + 188 = 8* 2^x - (1/2)^(3-x);2^(x+1) + 188 = 8*2^x - 2^(x - 3);2*2^x + 188 = 8*2^x  - 2^x * 2^(-3);8*2^x - 2* 2^x - 1/8  * 2^x = 188;47/8  * 2^x = 188;   /:47/8;2^x = 188 * 8/47;2^x = 32; 2^x = 2^5; x = 5