решите пожалуйста
1/2log_0.4(5*x+1)=log_0.4(x-1)

1/2log_0.4(5*x+1)=log_0.4(x-1)√(5x + 1) = x - 1ОДЗ: x - 1 > 0, x > 1(√(5x + 1))^2 = (x - 1^25x + 1 = x^2 - 2x + 1x^2 - 7x = 0x(x - 7) = 0x1 = 0x2 = 7