2sin^2x+sinx=1 ; ^2- квадрат
Помогите решить

2sin^2x + sinx = 12sin^2x + sinx - 1 = 0sinx = t2t^2 + t - 1 = 0D = 1 + 4*2*1 = 9t1 = (-1 - 3)/4t1 = - 1t2 = (-1 + 3)/4t2 = 1/21)  sinx = - 1x1 = - π/2 + 2πn, n∈Z2)  sinx = 1/2x = (-1)^n*arcsin(1/2) + πk, k∈Zx2 = (-1)^n*(π/6)+ πk, k∈Z