Помогите решить неравенства: 2cos(pi-x)<=1 и -4tg(x+pi/8)<=1

1)  2cos(π - x) ≤ 1cos(π - x) ≤ 1/2cos(x - π) ≤ 1/2arccos(1/2) + 2πn ≤ x - π ≤ 2π - arccos(1/2) + 2πn, n∈Zπ/3 + 2πn ≤ x - π ≤ 2π - π/3 + 2πn, n∈Zπ/3 + 2πn ≤ x - π ≤  5π/3 + 2πn, n∈Zπ/3 + π + 2πn ≤ x  ≤  5π/3 + π + 2πn, n∈Z4π/3  + 2πn ≤ x  ≤ 8π/3 + 2πn, n∈Z2)  - 4tg(x + π/8) ≤ 1tg(x + π/8)  ≥ - 1/4arctg(-1/4) + πn  ≤  x  ≤ π/2 + πn, n∈Z- arctg(1/4) - π/8+ πn  ≤  x  ≤ π/2  -  π/8+ πn, n∈Z- arctg(1/4) - π/8 + πn  ≤  x  ≤ 3π/8 + πn, n∈Z