Доля особей аа в большой популяции равна 0,49. Какая часть популяции гетерозиготна по гену А?

Доля особей аа в большой популяции равна 0,49. Какая часть популяции гетерозиготна по гену А?
- Предмет:
  Биология
- Автор:
  faithpowell
- 5 лет назад

Ответы 1

Закон Харди-Вайнберга p + q = 1; $p^{2} +2pg+ g^{2} =1$

p - частота встречаемости гена A; q - частота встречаемости гена a; $p^{2}$ - частота встречаемости доминантных гомозигот (АА); 2pq - частота встречаемости гетерозигот (Aa); $g^{2}$ - частота встречаемости рецессивных гомозигот (aa).

= 0,49

q= √ 0,49 =0,7

p = 1-0,7 =0,3

2pq =2* 0,7*0,3 = 0,42

Частота встречаемости гетерозигот (Аа) 0,42 или 42%
- Автор:
  crosby
- 5 лет назад
- 0
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Доля особей аа в большой популяции равна 0,49. Какая часть популяции гетерозиготна по гену А?

Ответы 1

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