Задача по электротехнике
Решите задачу плиз

R(экв) =0,4+(18/11)=2,0(36) Ом I(общ) = U/R=10/2,036=4,9 AU8=I*R8=1,96 BI5=I6=I7=(U-U8)/(R5+R6+R7)=8,04/9=0,89(3) AU(2,4)=U-U8=8,04 B

R(5-7)=R5+R6+R7=R(2,4)=R2+R4=R(1,3)=R1+R3=R(1-7)={R(1,3)*R(2,4)*R(5-7)}::{R(1,3)*R(2,4)+R(2-4)*R(5-7)+R(1,3)*R(5-7)}= ̰R̰э̰к̰в̰=R(1-8)=R(1-7)+R8= ̰Ḭо̰б̰щ̰=I8=U/Rэкв= ̰Ṵ8̰=I*R8= ̰Ṵ(̰2̰,̰4̰)̰=U(1,3)=U(5-7)=U-U8= ̰Ḭ5̰=I6=I7=U(5-7)/R(5-7)=