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Какая сила действует на заряд 12 нКл, помещённый в электростатическое поле с напряжённостью 10 кВ/м? С подробным решением пожалуйста.
Ответы 1
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Все делается в одно действие:q=12*10^-9 Кл E=10^4 В/м F-?F=q*E=12*10^-9*10^4=12*10^-5 H
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Автор:
laddierichard - 5 лет назад
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