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Камень массой 1 кг бросили вертикально вниз с высоты 30 метров с начальной скоростью 10 м/c. Найдите скорость во время падения,время падения,начальную и конечную энергию
Ответы 1
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Потенциальная энергия:Ep = m*g*h = 1*10*30 = 300 ДжИзменение кинетической энергии:ΔEк = m/2 (V2² - V1²) = 0,5(30²-25²) = 135,7 ДжВнутренняя энергия:ΔU = Ep - ΔEк = 300 - 135,7 = 164,3 Дж
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Автор:
jadaifjb - 5 лет назад
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