Тело брошено со скоростью υо с высоты h вверх под углом α к горизонту и упало через промежуток времени t на расстоянии ℓ (по горизонтали) от места бросания. Определить угол α, если υо=25м/с; h=7,5м; t=4,1с.

Тело брошено со скоростью υо с высоты h вверх под углом α к горизонту и упало через промежуток времени t на расстоянии ℓ (по горизонтали) от места бросания. Определить угол α, если υо=25м/с; h=7,5м; t=4,1с.
- Предмет:
  Физика
- Автор:
  vicentei7o7
- 6 лет назад

Ответы 2

Спасибо!
- Автор:
  ramirorxby
- 6 лет назад
- 0
Из условия движения тела: $h+Vo*t*sin \alpha - \frac{g*t^2}{2} =0.$ находим $sin \alpha = \frac{ \frac{gt^2}{2}-h }{Vo*t} = \frac{ \frac{9,81*4,81^2}{/2}-7,5 }{25*4,1} =0,731249268.$ Отсюда α = 0,820152 радиан = 46,9912 градуса.
- Автор:
  taco59
- 6 лет назад
- 0
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