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определите число электронов, прошедших через поперечное сечение проводника сопротивлением 30 ом за 27 мин падение напряжения на провонике 408В
Ответы 1
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I=U/R=408/3013,6 AN=q/e=I*t/e=13,6*27*60/1,6*106-19=1377*10^20
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Автор:
blondie7snz - 6 лет назад
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