участок электрической цепи,схема которой приведена на рисунке,состоит из двух последовательно соеденённых проводников.Сопротивление 2 проводника R2=8м напряжение на первом проводнике =2в а между точками а б 10 =10в опредилите мощность в первом проводнике

участок электрической цепи,схема которой приведена на рисунке,состоит из двух последовательно соеденённых проводников.Сопротивление 2 проводника R2=8м напряжение на первом проводнике =2в а между точками а б 10 =10в опредилите мощность в первом проводнике
- Предмет:
  Физика
- Автор:
  bowman
- 5 лет назад

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Напряжение на втором проводнике U2=10-U1=10-2=8 В, ток на участке цепи i=U2/R2=8/8=1 А. Сопротивление первого проводника R1=U1/i=2/1=2 Ом. Искомая мощность P1=i²*R1=1²*2=2 Вт. Ответ: P1=2 Вт.
- Автор:
  mauricio721
- 5 лет назад
- 0
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