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сосуд содержащий 3 кг воды при температуре 20 градусов, опустили стальную деталь массой 200 г нагретую до температуры 400 градусов, до какой температуры нагреется вода.
Св=4200 дж/кг*К
Сст=460дж/кг *К-
Предмет:
Физика -
Автор:
nemoconway - 5 лет назад
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Ответы 1
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Q1=Q2Q1=mв*св*(t-tв)Q2=mд*cд(tc-t)t-неизвестное подставляем значение
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Автор:
maximusmccoy - 5 лет назад
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