Маленький шарик массой 1 г и зарядом 2 мккл подвешен на непроводящей нерастяжимой нити в однородном электрическом поле, напряженность которого направлена горизонтально. Нить отклонилась от вертикали на угол 45 градусов. Найти напряженность электрического поля

Маленький шарик массой 1 г и зарядом 2 мккл подвешен на непроводящей нерастяжимой нити в однородном электрическом поле, напряженность которого направлена горизонтально. Нить отклонилась от вертикали на угол 45 градусов. Найти напряженность электрического поля
- Предмет:
  Физика
- Автор:
  lance
- 6 лет назад

Ответы 1

В проекциях:T*sina-q*E=0m*g-T*cosa=0T=m*g/cosam*g*tga=q*EE=m*g*tga/q=10^-3*10*1/5*10^-6=4*10^3 В/м
- Автор:
  dane
- 6 лет назад
- 0
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