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На рисунке представлен график движения автобуса из пункта А в пункт Б и обратно. Пункт А находится в точке x = 0, а пункт Б — в точке x = 30 км. Найдите сколько времени занял весь путь, если известно, что скорость автобуса на пути из пункта А в пункт Б была равна 60 км/ч. Ответ в мин.
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Предмет:
Физика -
Автор:
carlosplhb - 6 лет назад
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Ответы 1
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Движение равномерное, с постоянной скоростью x=Vt, из А в Б за t=30/60= 0.5час=30мин. Цена 1 деления по оси времени с=30/9 мин/дел обратный путь занял 3дел*30/9 мин/дел=10 мин, всего 30+10=40 мин -ответ
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Автор:
patricia8 - 6 лет назад
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