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При подъеме груза массой 100 кг на высоту 5 м с подъемным механизмом с КПД 70%,затраченная (полная)работа составит (Дж)?
Ответы 2
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Азатр=Аполезная/КПД, Аполезная=Епот=mgh, Азатр=100*10*5/0.7= 7143 Дж
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Автор:
leilani - 5 лет назад
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0
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70%=0,7
η=Ап/Аз=mgh/Аз
Аз=mgh/η
Аз=100•9,8•5/0,7=7000 Дж= 7 кДж
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Автор:
millieoozy - 5 лет назад
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0
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