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На стеклянную пластину с показателем преломления 1.5 падает луч света под углом 25°. Определите угол преломление и скорость света в стекле.
Ответы 1
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n=1.5 α=25 β=? v=?
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n=sinα/sinβ
sinβ=sinα/n=0.423/1.5≈0.28
β=arcsin0.28≈16°
v=c/n=3*10^8/1.5=2*10^8 м/с
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Автор:
sophiakeza - 6 лет назад
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