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парашутист рівномірно опускається зі швидкістю 5м/с. сила опору повітря за 20 с спуску виконує роботу 75 кДж. визначити масу парашутиста
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Предмет:
Физика -
Автор:
alfredopfcy - 6 лет назад
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Ответы 1
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v=5 м/с t=20 c A=75*10^3 Дж m=?
===
A=m*g*h
h=v*t
m=A/(g*v*t)=75*10^3/(10*5*20)=75 кг
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Автор:
titus9kwq - 6 лет назад
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