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Тело движется по окружности радиусом 5 м со скоростью 40 м/с. Чему равна частота обращения тела (об/с)?
Ответы 1
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Ответ:
1,27 об/с
Объяснение:
Дано:
R=5 м
v=40 м/с
Найти:
n-?
n=v/2piR=40/2*3,14*5=4/3,14=1,27 об/с
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Автор:
verónicamdxc - 5 лет назад
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!25 БАЛЛОВ!
Построить треугольник MNK: 1) по двум катетам и углу равному 90 градусов; 2) построить равнобедренный треугольник и по основанию (NK) -
ПОМОГИТЕ РЕШИТЬ УРАВНЕНИЕ 2^(2x+5)*5^(3x)*7^(4x-5)=1400^(5-x).
То что в скобках-это степени, * - это знак умножения.
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