Ответ: CuS0₄, MgCI₂, S0₂, HN0₃, NH₄CI1) 2Na0H+CuSO₄=Cu(0H)₂+Na₂S0₄
2Na⁺ +2OH⁻+ Cu2⁺+S0₄2⁻=Cu(0H)₂+2Na⁺+S0₄2⁻
20H⁻+Cu2⁺=Cu(0H)₂2) 2NaOH+MgCI₂=Mg(OH)₂+2NaCI
2Na⁺+20H⁻+Mg2⁺+2CI=Mg(0H)₂+2Na⁺+2Cl⁻
20H⁻+Mg2⁺=Mg(0H)₂3) Na0H+HN0₃=NaN0₃+H₂0
Na⁺+0H⁻+NO₃⁻+H⁺= Na⁺+N0₃+H₂0
0H⁻+H⁺=H₂04) Na0H+NH₄Cl=NH₃+H₂0+NaCI
CI⁻+Na⁺+OH⁻+NH₄⁺= Cl⁻+Na⁺+NH₃+H₂0
OH⁻+NH₄⁺=NH₃+H₂0
Автор:
arielwf6mДобавить свой ответ