t = 10 с.
V = 0 м/с.
g = 9,8 м/с^2.
μ = 0,05.
V0 - ?
Запишем 2 закон Ньютона в векторной форме: m *a = m *g + Fтр + N, где m - масса тела, a - ускорение тела, g - ускорение свободного падения, Fтр - сила трения, N - сила реакции льда.
ОХ: m *a = Fтр.
ОУ: 0 = m *g - N.
Fтр = μ *N = μ *m *g.
m *a = μ *m *g.
Тело движется с ускорением а, которое определяется формулой: a = μ *g.
a = (V - V0)/t, так как V = 0 м/с, тело остановилось, то формула примет вид: a = - V0/t.
Знак \"-\" означает, что ускорение а, направленное в противоположенную сторону движению.
μ *g = V0/t.
V0 = μ *g *t.
V0 = 0,05 *9,8 м/с^2 *10 с = 4,9 м/с.
Ответ: начальная скорость камня составляла V0 = 4,9 м/с.
Автор:
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