-определите объем железного бруска ,на который при погружении в спирт действует выталкивающая сила 19,6 Н
F(Архимеда)=p(плотность жидкости)*g*Vт(объем тела):
Отсюда можем выразить объем бруска:
p(спирта)=790
19,6=790*9,8*V
V=19,6/7742=0,0025м3
Ответ:0,0025м3
Автор:
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