в колебательный контур включен конденсатор емкостью 200 пФ. Какую индуктивность нужно включить в контур, чтобы в нем электрические колебания с частотой 400 кГц
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ФизикаАвтор:
purificaciónmdz2γ=1/2π√LC ⇒
L=1/γ²4π²C²
γ=400кГц=4*10⁵
с=200пФ=2*10⁻¹⁰ подставить и посчитать....
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cinnamondemtДобавить свой ответ
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