Один катетпрямоугольного треугольника АВ, другой ВС, то АМ - биссектриса, т.е.
АМ/МС=АВ/АС.=20/15, значит АВ=20х АС=15х ВС=35
Применим теорему Пифагора и х=1,4 Р=20х+15х+35=35х+35=35(1+1,4)=84
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