Одно из оснований трапеции в 3 раза больше другого. Средняя линия трапеции равна 12 см. Найдите каждую основание трапеции.

Одно из оснований трапеции в 3 раза больше другого. Средняя линия трапеции равна 12 см. Найдите каждую основание трапеции.
- Предмет:
  Геометрия
- Автор:
  faith
- 6 лет назад

Ответы 1

Так как сумма оснований трапеции равна средней линии, умноженной на 2, то
сумма оснований равна 12*2=24
Так как одно основание в 3 раза больше другого, то составим уравнение
х+3х=24 ,где х-основание меньшего основания
4х=24
х=6
Первое основание=6
Второе=6*3=18
- Автор:
  venanciofqxq
- 6 лет назад
- 0
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Одно из оснований трапеции в 3 раза больше другого. Средняя линия трапеции равна 12 см. Найдите каждую основание трапеции.

Ответы 1

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