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To find the unknown sides and angles in a right-angled triangle, the Pythagorean theorem and trigonometric functions can be used.
Given two legs:
a) a = 3, b = 4, c = sqrt(a^2 + b^2) = 5
Angle A can be found using the tangent function: tan A = b/a = 4/3.
b) a = 9, b = 10, c = sqrt(a^2 + b^2) = 15
Angle A can be found using the tangent function: tan A = b/a = 10/9.
c) a = 20, b = sqrt(c^2 - a^2) = sqrt(400 - 400) = sqrt(0) = 0
Angle A can be found using the tangent function: tan A = b/a = 0/20.
d) a = 11, b = 60, c = sqrt(a^2 + b^2) = 61
Angle A can be found using the tangent function: tan A = b/a = 60/11.
e) a = 5, b = 1, c = sqrt(a^2 + b^2) = sqrt(26) = 5.1
Angle A can be found using the tangent function: tan A = b/a = 1/5.
Given hypotenuse and leg:
a) c = 13, a = 5, b = sqrt(c^2 - a^2) = sqrt(169 - 25) = sqrt(144) = 12
Angle A can be found using the tangent function: tan A = b/a = 12/5.
b) c = 17, a = 7, b = sqrt(c^2 - a^2) = sqrt(289 - 49) = sqrt(240) = 15
Angle A can be found using the tangent function: tan A = b/a = 15/7.
c) c = 85, a = 84, b = sqrt(c^2 - a^2) = sqrt(7225 - 7056) = sqrt(169) = 13
Angle A can be found using the tangent function: tan A = b/a = 13/84.
d) c = 25, A = 50°20', a = c * cos A = 25 * cos 50°20'
b = c * sin A = 25 * sin 50°20'
e) c = 16, A = 76°21', a = c * cos A = 16 * cos 76°21'
b = c * sin A = 16 * sin 76°21'
Given leg and angle:
a) a = 5, A = 40°48', c = sqrt(a^2 / (tan A)^2 + a^2) = sqrt(25 / (tan 40°48')^2 + 25)
b = a * tan A = 5 * tan 40°48'
b) a = 9, A = 68°, c = sqrt(a^2 / (tan A)^2 + a^2) = sqrt(81 / (tan 68°)^2 + 81)
b = a * tan A = 9 * tan 68°
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