Помогите найти решение.

sin(<BAC)^2 + cos(<BAC)^2 = 1sin(<BAC)^2 = 1 - 441/841sin(<BAC)^2 = 400/841sin(<BAC) = 20/29BH/BA = 20/2910/BA = 20/29BA = 29*10/20BA = 29/2BA = 14,5BA^2 = AH^2 + BH^2210,25 = AH^2 + 100110,25 = AH^2AH = 10,5CH = AH - ACCH = 10,5 - 6,5CH = 4