В треугольнике АВС угол А=90, а угол С на 40 больше угла В. Найдите углы В и С.
это будет прямоугольный треугольник,
так,
как известно сумма 3х сторон треуг. = 180 градусам
известно что А=90
180-90=90
и 90-40=50
угол В=40
угол С=50
(ЧИСЛА ВСЕ В ГРАДУСАХ)
Автор:
salvadorjtmw
1)180-90=40(г)-угол В
2)90-40=50(г)-угол С=50
Ответ:40,50.
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