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Найдите сторону треугольника лежащую против угла в 150 если две другие стороны равны 4 корне из 3 см и 7см
Ответы 1
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Обозначим неизвестную сторону х. cos150°= -cos30°= -√3/2По т.косинусов:х²=(4√3)²+7² - 2•4√3•7•(-√3/2)x²=48+49+84 x=√181 см
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Автор:
adeline - 6 лет назад
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