Сколько литров аммиака NH^3 можно получить при взаимодействии 112л азота с водородом? - №11282376

Сколько литров аммиака NH^3 можно получить при взаимодействии 112л азота с водородом?
- Предмет:
  Химия
- Автор:
  odiefze7
- 6 лет назад

Ответы 1

N2 + 3H2 ----> 2NH3 n(N2) = 112/ 22,4 = 5 моль n(NH3)=2n(N2)=10 моль V(NH3)=10*22,4=224 литра
- Автор:
  aurelia
- 6 лет назад
- 0
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