Сколько молекул содержится в порции воды массой 90г
Предмет:
ХимияАвтор:
orlandowqjmN = Na×n, n = m : M
M (H₂O) = 1·2 + 16 = 2 + 16 = 18 г/моль
n = 90г : 18 г/моль = 5 моль
N (H₂O) = 6·10²³ молекул · 5 моль = 30·10²³ молекул
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