Любой газ количеством 1 моль при н.у. занимает объем равный 22.4 л.Если дан метан 5.6 л., значит он содержит 5,6/22,4=0,25 моль метана (n = V/Vо Vo - молярный объем, n - количество вещества, а V - данный объем).
N=nV, где N- число молекул,n - количество вещества, а V - данный объем
N=0.25*5,6= 1.4
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