Помогите с задачей! Какую массу оксида меди можно получить при разложении 49 г гидроксида?
Уравнение:
Cu(OH)2 = CuO + H2O
Рассчитаем количество вещества гидроксида меди:n = m/M = 49г/98г/моль = 0,5 моль
По уравнению реакции:n(CuO) = n(Cu(OH)2) = 0,5 моль
Рассчитаем массу оксида:m = n*M = 0,5моль*80г/моль = 40 грамм
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amityДобавить свой ответ
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