Определите молекулярную формулу органического соединения с составом 80% углерода и 20% водорода если плотность его по воздуху равна 1,034

Определите молекулярную формулу органического соединения с составом 80% углерода и 20% водорода если плотность его по воздуху равна 1,034
- Предмет:
  Химия
- Автор:
  lanesutton
- 6 лет назад

Ответы 2

Пусть простейшая формула вещества СхНy.Рассчитываем атомные факторы:Аф С = 80/12 = 6,7Аф Н = 20/1 = 20 Х : У = 6,7 : 20 = 1 : 3Простейшая формула СН₃ с массой (12+3) = 15Молярная масса вещества равна 29 х 1,034 = 3030/15 = 2 ⇒ Х = 2; У = 6Это этан С₂Н₆
- Автор:
  demetrius
- 6 лет назад
- 0
C2H6Подробное решение смотри на фото
- Автор:
  moniquelnyj
- 6 лет назад
- 0
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Определите молекулярную формулу органического соединения с составом 80% углерода и 20% водорода если плотность его по воздуху равна 1,034

Ответы 2

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