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Массовая доля H2O в смеси CuSO4*5H2O и FeSO4*7H2O равна 41,59%. Чему равна массовая доля CuSO4* 5H2O в смеси? Помогите пожалуйста заранее благодарна!!
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Предмет:
Химия -
Автор:
alejandra55 - 6 лет назад
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Ответы 5
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Спасибо тебе большое!!! Ты очень умный!!
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Автор:
miss kittyclay - 6 лет назад
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0
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А не мог бы ты посмотреть другие мои задачи? Я была бы тебе очень очень благодарна!
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Автор:
madisonbrown - 6 лет назад
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0
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давайте завтра
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Автор:
rosa46 - 6 лет назад
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0
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спасибо!!
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Автор:
mookiex523 - 6 лет назад
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0
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допустим имеется 100 г смеси... массы воды там 41,59г количества вещества воды 41,59/18=2,31моль предположим,что в смеси имеется х моль CuSO4*5H2O и у моль FeSO4*7H2O,тогда составляем систему 250х+278У=1005х+7у=2,31 х=0,16моль масса CuSO4*5H2O= 0,16*250=40г или 40%
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Автор:
samirdodson - 6 лет назад
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0
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