Какой объём 15%-ного (пл.1.16 г/мл) раствора гидроксида натрия необходим для полной нейтрализации 200 мл 30%-ного раствора серной кислоты(пл. 1.22 г/мл)

Какой объём 15%-ного (пл.1.16 г/мл) раствора гидроксида натрия необходим для полной нейтрализации 200 мл 30%-ного раствора серной кислоты(пл. 1.22 г/мл)
- Предмет:
  Химия
- Автор:
  salomé
- 5 лет назад

Ответы 1

NaOH + CH3COOH ---> CH3COONa + H2O m(CH3COOH) = 600 * 0,2 = 120 г v(CH3COOH) = 120 / 80 = 2 моль => v(NaOH) = 2 моль m(NaOH) = 2 * 40 = 80 г V(NaOH) = 80 / 1,22 = 65,57 мл Vр-ра (NaOH) = 65,57 * 100 / 20 = 327,86 мл Ответ: Vр-ра (NaOH) = 327,86 мл
- Автор:
  aubriebxhz
- 5 лет назад
- 0
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Какой объём 15%-ного (пл.1.16 г/мл) раствора гидроксида натрия необходим для полной нейтрализации 200 мл 30%-ного раствора серной кислоты(пл. 1.22 г/мл)

Ответы 1

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