Сколько грамм Al содержится в 100 граммах солей: 1)AlBr3 2)Al(NO3)3 3)Al2(SO4)3 4)AlPO4 5)Al2S3

1) m(Al)=100g*W(Al)W(Al)= =  = 0.101m(Al)=100g*0.101=10.1g2) m(Al)=100g*W(Al)W(Al)==≈0.127m(Al)=100g*0.127=12.7g3) m(Al)=100g*W(Al)W(Al)=Mr(Al)/Mr(Al2(SO4)3)=54/342≈0.158m(Al)=100g*0.158=15.8g4) m(Al)=100g*W(Al)W(Al)=Ar(Al)/Mr(AlPO4)=27/122≈0.221m(Al)=100g*0.221=22.1g5)m(Al)=100g*W(Al)W(Al)=Mr(Al)/Mr(Al2S3)=54/150=0.36m(Al)=100g*0.36=36g.