Нужно рассчитать массовую долю элементов:
1.H2SO4
2.HNO3
3.H2CO3
4.KMnO4
5.K2C2O7

1)M(h2so4) = 98 г/мольw(h)=(2/98)*100=2.04%w(s)=(32/98)*100=32.65%w(o)=(64/98)*100=65.31%2)M(HNO3)=63 г/мольw(h)=(1/63)*100=1.59%w(n)=(14/63)*100=22.22%w(o)=(48/63)*100=76.2%3)M(H2CO3)=62 г/мольw(h)=(2/62)*100=3.23%w(c)=(12/62)*100=19.05%w(o)=(48/62)*100=77.42%4)M(KMnO4)=158 г/мольw(K)=(39/158)*100=24.96%w(Mn)=(55/158)*100=34.81%w(o)=(64/158)*100=40.51%5)M(K2C2O7)=214 г/мольw(K)=(78/214)*100=36.45%w(c)=(24/214)*100=11.215%w(o)=(112/214)*100=52.34%