H2SO4
AE(OH)3
C12H22O11
Найти молекурную масу

МолекулярнаяMr (Al(OH)3) =Ar(Al)+3Ar(O)+3Ar(H)=27 + 16*3 + 1*3 = 78 г/мольMr (H2SO4) = 2 Ar (H) + Ar (S) + 4 Ar (O) = 2•1+32+4•16 = 98;Mr (C12H22O11) = 12 Ar (C) +22 Ar (H) +11 Ar (O) = 12•12+22•1 +11•16 = 342.