К 80г 20% раствора сахара добавили еще 15г сахара. Определите массовую долю сахара во вновь приготовленном растворе. С вычислениями.

К 80г 20% раствора сахара добавили еще 15г сахара. Определите массовую долю сахара во вновь приготовленном растворе.

С вычислениями.
- Предмет:
  Химия
- Автор:
  camren
- 5 лет назад

Ответы 1

Дано:m1(раствора)=80гw1(C12H22O11)=20%m1(C12H22O11)=15гНайти:w2(C12H22O11)-?Решениеm2(C12H22O11)=m1(раствора)×w1(C12H22O11)=80г×0,2=16гm2(раствора)=m1(раствора)+m1(C12H22O11)=80г+15г=95гm3(C12H22O11)=m1(C12H22O11)+m2(C12H22O11)=15г+16г=31гw2(C12H22O11)=m3(C12H22O11)÷m2(раствора)=31г÷95г≈0,3263=32,63%Ответ: w2(C12H22O11)=32,63%
- Автор:
  cristalmora
- 5 лет назад
- 0
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К 80г 20% раствора сахара добавили еще 15г сахара. Определите массовую долю сахара во вновь приготовленном растворе. С вычислениями.

Ответы 1

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К 80г 20% раствора сахара добавили еще 15г сахара. Определите массовую долю сахара во вновь приготовленном растворе.

С вычислениями.