1)даноm(CuSO4)=1.6g-------------------n(NaOH)-?CuSO4+2NaOH-->Cu(OH)2+Na2SO4M(CuSO4)=160 g/moln(CuSO4)=m/M=1.6/160=0.01 moln(CuSO4)=2n(NaOH)=2*0.01=0.02 molответ 0.02 моль2)даноm(Fe)=2.7 gFe2O3-----------------V(H2)-? X 2.7Fe2O3+3H2-->2Fe+3H2O M(Fe)=56 g/mol Vm=22.4L/mol 3*22.4 2*56X=67.2*2.7/112=1.62Lответ 1.62 л3)даноm(O2)=5.6 g-----------------m(P)-? X 5.64P + 5O2-->2P2O5 M(P)=31 g/mol M(O2)=32g/mol4*31 5*32X=124*5.6/160=4.34 gответ 4.34 г