Задача по химии! m(m,r)-100г w(SO4)-2,5% ___________ m-(ZnSO4) m(H2O)-? Решите

Задача по химии!
m(m,r)-100г
w(SO4)-2,5%
___________
m-(ZnSO4)
m(H2O)-?
Решите пожалуйста!
- Предмет:
  Химия
- Автор:
  gasbyfa9o
- 4 года назад

Ответы 1

Решениемасса всего раствора равна 100 гра массовая доля ZnSO4 = 2,5 %находим массу ZnSO4 (m)составим пропорцию, возьмем массу всего р-ра как за 100% , а массу ZnSO4 как за Х :100 гр - 100% Х - 2,5% Х = 100 х 2,5 / 100 = 2,5 гр m(ZnSO4)чтобы найти массу воды отнимим от всего раствора массу ZnSO4 :100 - 2,5 = 97,5 гр m(H2O)
- Автор:
  lanehurr
- 4 года назад
- 0
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Задача по химии! m(m,r)-100г w(SO4)-2,5% ___________ m-(ZnSO4) m(H2O)-? Решите пожалуйста!

Ответы 1

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Задача по химии!
m(m,r)-100г
w(SO4)-2,5%
___________
m-(ZnSO4)
m(H2O)-?
Решите пожалуйста!