Помогите решить цепочку:
1)CaC[tex] O_{3}[/tex] -> Ca[tex] C_{2}[/tex]=>[tex] C_{2}H_{2} =\ \textgreater \ C_{6}H_{6}[/tex]

2) [tex] C_{2}H_{2} =\ \textgreater \ H_{3} - CHO =\ \textgreater \ CH_{3}CH_{2}OH
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3) [tex] C_{2}H_{2} =\ \textgreater \ C_{2}H_{4}
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Спасибо огромное!

1)CaCO3 + 4C = CaC2 + 3CO CaC2 + 2H2O = Ca(OH)2 + C2H23С2Н2  =  С6Н6 (t, C)2)C2H2 + H2O = CH3CHO CH3CHO + H2 = CH3CH2OH3)C2H2 + H2 = C2H4 (катализатор - Ni, Pt)